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7Applications
7.11 Roller conveyor
138
Lenze · Drive Solution Designer · Manual · DMS 4.2 EN · 12/2013 · TD23
_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _
Total moment of inertia
[7-121] Equation 4: Total moment of inertia
Stationary torque
The stationary part of the torque consists of different individual forces:
[7-122] Equation 5: Stationary torque
[7-123] Equation 6: Friction force
[7-124] Equation 7: Lifting force
If the transported material drives against a limit stop (e. g. adjustment of the material), the force
F
add
is generated:
[7-125] Equation 8: Friction force
The mass of the payload is calculated by the line load:
[7-126] Equation 9: Mass of the payload
Required torque of the application (without losses)
In order to take the efficiency of the application by the transmission of the movement via chains
into consideration, first the required torque of the application has to be determined:
[7-127] Equation 10: Required torque of the application (without losses)
J
sum
m
L
d
aux
2 1000 /
mm
m
------------------------------------



2
J
aux
+=
M
sds
F
μ
F
g
F
add
++()
d
aux
2 1000 /
mm
m
------------------------------------
=
F
μ
m
L
g βcos
2
d
aux
-----------
fd+
Brg
μ
Brg
()
v
v
-----
⋅⋅ =
F
g
m
L
g βsin⋅⋅=
F
add
m
add
g βcos μ
L
v
v
-----
⋅⋅ =
m
L
m’
L
l=
M
App
M
sds
J
sum
α+=
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